posted August 10, 2000 02:12 PM         

This should print out a checkbox, checked if it is supposed to be, and take an argument to be passed when the user chooses to update the page.
When I submit my form, all of the checkboxes pass a value of zero even when they are checked.
Can you tell me if there is an error in this statement?

print "<td valign='top'>";
print "<input type=checkbox name=checkbox_$cat_name value='checked' $checked[$j]></td>";
print ${"checkbox_".$field_name}." !!!";
print "<td valign='top'>$list_cat_name</td>";

$checked[$j] - contains the value 'checked' or nothing set (correctly) earlier in the file
the checkboxes are named checkbox_(fieldname) [ex: checkbox_food]

The value 'checked' is passed to another file that updates the db

posted August 10, 2000 08:01 PM            

tigg,

i think you should put value="1" in check box.

ie,

echo "<input type=\"checkbox\" name=\"checkbox_".$cat."_name\" value=\"1\" $checked[$j]></td>";

i hope that will solve your problem..

------------------
SR -
webshiju.com

posted August 11, 2000 01:25 PM            

<input type="checkbox" value="show_email" name="show_email" <? if ($show_email == "show_email") echo "checked"; ?>>

This works like a charm! I'm just checking to see if @show_email has already been set, and if so, just output CHECKED, which turns on the checkbox. Hope this helps for you.