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base64_encode (PHP 3, PHP 4 ) base64_encode -- Zakódovat data pomocí MIME base64 Popisstring base64_encode ( string data)
base64_encode() vrátí
data zakódovaný pomocí base64. Toto kódování
je navrženo tak, aby umožnilo binárním datům přežít transport přenosovými
vrstvami, které nejsou osmibitové, jako jsou například těla emailů.
Data kódovaná pomocí base64 zabírají o zhruba 33% prostoru více než původní
data.
Viz také:
base64_decode(),
chunk_split(),
RFC-2045 sekce 6.8.
User Contributed Notes
base64_encode |
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bullshit at burk dot dhs dot org
15-May-2002 11:14 |
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There seems to be a problem using the base64_encode() under win32
envariments. I have recived some mails about it. It works fine under
linux. The base64_decode() seems to work fine under both os.
Best
regards,
Rolf
http://php.holtsmark.no/base64img/
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23-Jul-2002 07:58 |
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testing it script.
<?php
$s = "this is test
data";
$e = base64_encode($s);
$d = base64_decode($e);
echo
"original data: $s<dd>\t" .
"encoded data:
$e<dd>\t" .
"decoded data:
$d<dd>\t";
?>
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emaman at upandup dot net
17-Sep-2002 12:43 |
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Here is a workaround for the base64_encode function under Win32.
1)
Download the base64.exe program from http://www.fourmilab.ch/.
2) Write
your own base64 encode function :
function mybase64_encode($s)
{
$tmpfname = tempnam("", "tmp");
$fp
= fopen($tmpfname, "w+");
if ( $fp ) {
fwrite ($fp, $s);
fclose($fp);
exec("c:/bin/base64 -e " . $tmpfname . " " . $tmpfname
. ".b64");
$fp = fopen($tmpfname .
".b64", "r");
$contents =
fread($fp,filesize($tmpfname . ".b64"));
fclose($fp);
unlink($tmpfname);
unlink($tmpfname
. ".b64");
return($contents);
}
}
With this function you don't need to call the chunk_split function.
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guy at bhaktiandvedanta dot com
02-Oct-2002 12:00 |
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You can use base64_encode to transfer image file into string text and then
display them. I used this to store my images in a database and display
them form there. First I open the files using fread, encoded the result,
and stored that result in the database. Useful for creating random images.
image.php:
<?
header(" Content-Type:
image/jpeg");
header(" Content-Disposition:
inline");
$sql = "SELECT data FROM image where
name='".$img."'";
$result = mysql_query($sql);
$row =
mysql_fetch_row($result);
$image = $row[0];
echo
base64_decode($image);
?>
And in the html file you
put:
<img src=/old?u=http%3A%2F%2Ffr.php.net%2Fmanual%2Fcs%2F%26quot%3Bimage.php%3Fimg%3Dtest3%26quot%3B&y=1999
border="0" alt="">
Guy Laor
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webmaster at mainbotics dot com
18-Nov-2002 07:49 |
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In response to guy at bhaktiandvedanta dot com:
You can simply save the
images in a blob field (Binary Large OBject) in the data base just by
using mysql_escape_string(), which escapes NULL, CR, LF, \x1A, ... and
other special-meaning characters, so you can directly insert the image
into the sql query without any problem and without any kind of encoding
(just the slashes). That way, you'll save space at the data base and when
you get the image, you can directly dump it to the browser without making
any kind of decoding. The script will so become faster and more efficient,
and MySQL is already aware about the field contains binary data, not text
data, to threat it in a convenient way.
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maarten dot malaise at pandora dot be
18-Dec-2002 07:27 |
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In addition to what "guy at bhaktiandvedanta dot com" and
"webmaster at mainbotics dot com" wrote above
Here's a full
example of how to upload a file and add it to a MySQL
database
create file "upload.htm" to select and upload a
file
<html>
<body>
<FORM
ENCTYPE="multipart/form-data" ACTION=/old?u=http%3A%2F%2Ffr.php.net%2Fmanual%2Fcs%2F%26quot%3Bupload.php%26quot%3B&y=1999
METHOD=POST>
<INPUT TYPE="hidden"
name="MAX_FILE_SIZE" value="65000">
Send this
file: <INPUT NAME="userfile"
TYPE="file">
<INPUT TYPE="submit"
VALUE="Upload
file">
</FORM>
</body>
</html>
create
file "upload.php" to add the file to the database (assuming that
you are adding the file to an existing record with a BLOB field named
"picture"):
<?
if (is_uploaded_file($userfile))
{
copy($userfile, $HTTP_POST_FILES['userfile']['name']);
} else
{
echo "error. File:
'$userfile'.";
}
$filename=$HTTP_POST_FILES['userfile']['name'];
$fd
= fopen ($filename, "r");
$contents = fread ($fd,
filesize($filename));
fclose($fd);
$escaped_contents=mysql_escape_string($contents);
//
Connecting, selecting database
$link =
mysql_connect("dbhost", "dbuser",
"dbpassword")
or die("Could not
connect");
mysql_select_db("databasename")
or
die("Could not select database");
// Performing SQL
query; assuming that the "picture" is a BLOB field
$query =
"UPDATE tablename SET picture='$escaped_contents' WHERE
id=1";
$result = mysql_query($query)
or die("Query
failed");
// Closing
connection
mysql_close($link);
?>
create
"view.php" to view the image (assuming that you uploaded a
GIF-formatted file):
<?
// Connecting, selecting
database
$link = mysql_connect("dbhost", "dbuser",
"dbpassword")
or die("Could not
connect");
#print "Connected
successfully";
mysql_select_db("databasename")
or
die("Could not select database");
header("
Content-Type: image/gif");
header(" Content-Disposition:
inline");
$sql = "SELECT picture FROM tablename WHERE
id=1";
$result = mysql_query($sql);
$row =
mysql_fetch_row($result);
$image = $row[0];
echo
$image;
?>
And finally: this is how you can use the image
in a HTML result file
<img
src=/old?u=http%3A%2F%2Ffr.php.net%2Fmanual%2Fcs%2F%26quot%3Bview.php%26quot%3B%26gt%3B%3Cbr&y=1999>
good luck,
Maarten Malaise
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