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vsprintf> <vfprintf
Last updated: Mon, 30 Oct 2006

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vprintf

(PHP 4 >= 4.1.0, PHP 5)

vprintf -- Output a formatted string

Description

int vprintf ( string format, array args )

Display array values as a formatted string according to format (which is described in the documentation for sprintf()).

Operates as printf() but accepts an array of arguments, rather than a variable number of arguments.

Returns the length of the outputted string.

See also printf(), sprintf(), vsprintf()



vsprintf> <vfprintf
Last updated: Mon, 30 Oct 2006
 
add a note add a note User Contributed Notes
vprintf
tehjosh at gamingg dot net
30-Jul-2007 04:19
To toolofthesystem at gmail dot com:

You don't need to use output buffering with vprintf() because you can use vsprintf(), which has the same functionality as vprintf(), except that it returns the resulting string instead of outputting it.
toolofthesystem at gmail dot com
27-Mar-2007 06:42
This function comes useful sometimes when trying to list information returned from MySQL:

function print_sql($query,$printf){
    $sql_sql = mysql_query($query);
    while($sql = mysql_fetch_row($sql_sql)){
        vprintf($printf,$sql);
    }
}

Unfortunately, this seems to sneak its way past output buffering when I tried creating an argument to allow it to be contained in a returned string... either that or I didn't do it right.
soylent at soylentgreens dot com
10-Dec-2006 10:49
I wanted to achieve (something like) this:

<?
$format
= "A %s %s %s.\n";

$array1 = Array("monkey", "cow", "rooster");
$array2 = Array("eats", "goes", "crows");
$array3 = Array("bananas", "moo", "in the morning");

printf($format, $array1, $array2, $array3);
?>

Output:
A monkey eats bananas.
A cow goes moo.
A rooster crows in the morning.

but I couldn't find any php function to put in for printf that would work (vprintf comes close).  So I created this little function (and used it to create a select box):

<?

/*
  printf_arrays( string format, [array args[, array ...]] )
*/

function printf_arrays($format) {
   
$args = func_get_args();
   
array_shift($args); // get rid of format
   
for($i=0; $i<count($args[0]); $i++) {
       
$pfargs = Array();
        foreach(
$args as $arr) $pfargs[] = (is_array($arr) && $arr[$i]) ? $arr[$i] : '';
       
vprintf($format, $pfargs);
    }
}

$months = Array(
 
'01'=>'Jan',
 
'02'=>'Feb',
 
/* etc. */
);

?>

<select name="month">
  <? printf_arrays('<option value="%s">%s</option>', array_keys($months), array_values($months)) ?>
</select>

Anyone else have any better ideas?  Is there a built-in php function I missed that does this already?
caleb at tekhawk dot com
29-Nov-2006 11:19
i know that you can use %1$s or %3$s to select the first or third string but how can you or can you use array names to select it

something like %'user'$s $'email'$s

i tend to add things to my databases over time and this could save loads of recoding
WebMaestro (asiby at hotmail dot com)
13-Mar-2005 09:40
<?php
$fruits
= array(1, 'banana',1, 'apples', 3, 'oranges', 2, 'peaches');

vprintf("I have %d %s, %d %s, %d %s and %d %s.", $fruits);
?>

Output:

I have 1 banana, 1 apples, 3 oranges and 2 peaches.

vsprintf> <vfprintf
Last updated: Mon, 30 Oct 2006
 
 
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