PHP: number_format

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number_format

keyg at auralplanet dot com
23-Nov-2004 03:56


if you want &nbsp; as a separator and use windows charset this piece of code may help:



<?php

$number=number_format($number,2,'.',chr(0xA0));

?>

brandonprudent at yahoo dot com
10-Oct-2004 08:52


To convert numbers to thier textual representations, you can use an adapted version of the Number::Spell Perl module. The PHP conversion can be found here: http://pear.php.net/package/Numbers_Words

GeekPrices Dot Com
07-Oct-2004 02:57


this also works as well



$number = "29346.99"; //value

echo "$" .number_format($number, 2, '.', ',');



produces $29,346.99

Svein Tjonndal (sveint at yahoo dot com)
15-Sep-2004 04:18


If you use space as a separator, it will break on that space in HTML tables...



Furthermore, number_format doesn't like '&nbsp;' as a fourth parameter. I wrote the following function to display the numbers in an HTML table.



  function numberfix($number)

  {

    $number = number_format($number,0,","," ");

    return str_replace(" ", "&nbsp;", $number);

  }



For use in:

<table><tr><td><?php echo $number; ?></td></tr></table>

drew at zitnay dot com
17-Aug-2004 08:17


A more reliable and concise way of doing what S. Rahmel was trying to do below is as follows:



<?php

$field_inhalt = str_replace(array(".", ","), array("", "."), $field_inhalt);

?>



The str_replace() call will first replace all dots with blanks, and then replace all commas with dots.  That way, it doesn't break down when you try a number over one million (i.e. 1.010.453,21).



Drew

mircea at vtds dot co dot uk
02-Jun-2004 06:57


This function formats numbers 'human readable':





function byte_format($input, $dec=0)


{ 


  $prefix_arr = array(" B", "K", "M", "G", "T");


  $value = round($input, $dec);


  $i=0;


  while ($value>1024)


  { 


     $value /= 1024;


     $i++;


  }


  $return_str = round($value, $dec).$prefix_arr[$i];


  return $return_str;


}

S. Rahmel
11-Mar-2004 11:47


if you converted a number to a German format with number_format() and want to save it in mySQL, you first have to change the number format back to an English format.



For example 

10.453,21 >>>> 10453.21



Here is an example how to do this:



    $field_array=explode(".", $field_inhalt);

    $field_inhalt=$field_array[0].$field_array[1];

    $foeld_array=explode(",", $field_inhalt);

    $field_inhalt=$field_array[0].".".$feld_array[1];

    $field_inhalt=sprintf($field_inhalt, 2);



$field_inhalt is the variable of the actual number you want to change to the english format.

chandu at chandu dot org
08-Mar-2004 02:29


People here in India are more used to counting money in Lakhs & Crores .. so here is the code for formatting the commas with thousands for the first time and then with hundred multiples from there after.



Ex: 1234567  ->  12,34,567



<?php



function makecomma($input)

{

    // This function is written by some anonymous person - I got it from Google

    if(strlen($input)<=2)

    { return $input; }

    $length=substr($input,0,strlen($input)-2);

    $formatted_input = makecomma($length).",".substr($input,-2);

    return $formatted_input;

}



function formatInIndianStyle($num){

    // This is my function

    $pos = strpos((string)$num, ".");

    if ($pos === false) { $decimalpart="00";}

    else { $decimalpart= substr($num, $pos+1, 2); $num = substr($num,0,$pos); }



    if(strlen($num)>3 & strlen($num) <= 12){

                $last3digits = substr($num, -3 );

                $numexceptlastdigits = substr($num, 0, -3 );

                $formatted = makecomma($numexceptlastdigits);

                $stringtoreturn = $formatted.",".$last3digits.".".$decimalpart ;

    }elseif(strlen($num)<=3){

                $stringtoreturn = $num.".".$decimalpart ;

    }elseif(strlen($num)>12){

                $stringtoreturn = number_format($num, 2);

    }



    if(substr($stringtoreturn,0,2)=="-,"){$stringtoreturn = "-".substr($stringtoreturn,2 );}



    return $stringtoreturn;

}



$num = 1234567;

echo  formatInIndianStyle($num);



?>

armstrong ~~at~~ rice ~~dot~~ edu
23-Feb-2004 01:33


I submitted this question earlier, but I found the answer myself.  To convert a number to its word form (e.g. 34 to "thirty four")  try the function below.  It turned out to be a lot more complex than I thought!



I'm using it for printing dollar ammounts, so the cents get printed like 13/100



I converted most of it from this java code http://mindprod.com/inwords.html so credit goes to him for doing the hard part.



<?

/**

* convert long integer into American English words.

* e.g. -12345 -> "minus twelve thousand forty-five"

* Handles negative and positive integers

* on range -Long.MAX_VALUE .. Long.MAX_VALUE;

* It cannot handle Long.MIN_VALUE;

*/



function num2words( $num ){

    $ZERO = "zero";

    $MINUS = "minus";

    $lowName = array(

          /* zero is shown as "" since it is never used in combined forms */

          /* 0 .. 19 */

          "", "one", "two", "three", "four", "five",

          "six", "seven", "eight", "nine", "ten",

          "eleven", "twelve", "thirteen", "fourteen", "fifteen",

          "sixteen", "seventeen", "eighteen", "nineteen");



    $tys = array(

          /* 0, 10, 20, 30 ... 90 */

          "", "", "twenty", "thirty", "forty", "fifty",

          "sixty", "seventy", "eighty", "ninety");



    $groupName = array(

          /* We only need up to a quintillion, since a long is about 9 * 10 ^ 18 */

          /* American: unit, hundred, thousand, million, billion, trillion, quadrillion, quintillion */

          "", "hundred", "thousand", "million", "billion",

          "trillion", "quadrillion", "quintillion");



    $divisor = array(

          /* How many of this group is needed to form one of the succeeding group. */

          /* American: unit, hundred, thousand, million, billion, trillion, quadrillion, quintillion */

          100, 10, 1000, 1000, 1000, 1000, 1000, 1000) ;



    $num = str_replace(",","",$num);

    $num = number_format($num,2,'.','');

    $cents = substr($num,strlen($num)-2,strlen($num)-1);

    $num = (int)$num;



    $s = "";



    if ( $num == 0 ) $s = $ZERO;

    $negative = ($num < 0 );

    if ( $negative ) $num = -$num;



    // Work least significant digit to most, right to left.

    // until high order part is all 0s.

    for ( $i=0; $num>0; $i++ ) {

        $remdr = (int)($num % $divisor[$i]);

        $num = $num / $divisor[$i];

        // check for 1100 .. 1999, 2100..2999, ... 5200..5999

        // but not 1000..1099,  2000..2099, ...

        // Special case written as fifty-nine hundred.

        // e.g. thousands digit is 1..5 and hundreds digit is 1..9

        // Only when no further higher order.

        if ( $i == 1 /* doing hundreds */ && 1 <= $num && $num <= 5 ){

            if ( $remdr > 0 ){

                $remdr += $num * 10;

                $num = 0;

            } // end if

        } // end if

        if ( $remdr == 0 ){

            continue;

        }

        $t = "";

        if ( $remdr < 20 ){

            $t = $lowName[$remdr];

        }

        else if ( $remdr < 100 ){

            $units = (int)$remdr % 10;

            $tens = (int)$remdr / 10;

            $t = $tys [$tens];

            if ( $units != 0 ){

               $t .= "-" . $lowName[$units];

            }

        }else {

            $t = $inWords($remdr);

        }

        $s = $t . " " . $groupName[$i] . " "  . $s;

        $num = (int)$num;

    } // end for

    $s = trim($s);

    if ( $negative ){

        $s = $MINUS . " " . $s;

    }



    $s .= " and $cents/100";



    return $s;

} // end inWords



?>

cruzf_AT_fibertel.com.ar
07-Nov-2003 08:03


You could add padding zeros like this:



<?

$number="129";

$number=sprintf("%08d",$number);

?>

j dot bos at bytewriters dot nl
01-Jun-2003 09:45


If I'm not mistaking all these examples of adding leading zeros will not really work with floats. Sometimes though one needs it to have it working with floats as well.



With the function below use 2, 3 or 5 parameters. Don't ask me why 4 don't work, the number_format() function seems to have problems with that. At least my version of PHP has that "feature".



function leading_zero( $aNumber, $intPart, $floatPart=NULL, $dec_point=NULL, $thousands_sep=NULL) {        //Note: The $thousands_sep has no real function because it will be "disturbed" by plain leading zeros -> the main goal of the function

  $formattedNumber = $aNumber;

  if (!is_null($floatPart)) {    //without 3rd parameters the "float part" of the float shouldn't be touched

    $formattedNumber = number_format($formattedNumber, $floatPart, $dec_point, $thousands_sep);

    }

  //if ($intPart > floor(log10($formattedNumber)))

    $formattedNumber = str_repeat("0",($intPart + -1 - floor(log10($formattedNumber)))).$formattedNumber;

  return $formattedNumber;

  }



echo leading_zero(21.12345678, 4, 5);    // Output: 0021.12346

echo leading_zero(21.12345678, 4);    // Output: 0021.12345678

echo leading_zero(21.12345678, 3, 0); // Output: 021

echo leading_zero(21.12345678, 3, 5, ",", ""); // Output: 021,12346



addition: Just like the number_format I haven't found a way *not* to round a number while changing the decimal point and the thousands seperator.

sgj at dr dot com
18-May-2003 03:04


Just an observation:

The number_format rounds the value of the variable.



$val1 = 1.233;

$val2 = 1.235;

$val3 = 1.237;



echo number_format($val1,2,",","."); // returns: 1,23

echo number_format($val2,2,",","."); // returns: 1,24

echo number_format($val3,2,",","."); // returns: 1,24

Theo Diem
24-Mar-2003 10:45


formatting numbers may be more easy if u use number_format function.



I also wrote this :

function something($number)

{

    $locale = localeconv();

    return number_format($number,

       $locale['frac_digits'],

        $locale['decimal_point'],

        $locale['thousands_sep']);

}



hope this helps =)

[]'s

andrew at crucible dot co dot nz
05-Jan-2002 01:56


Remember that number_format returns a string, so you shouldn't run a number_format on a variable that's already a product of number_format (it will only take the first token of the string)...





eg. echo number_format("123,456.00", 2);


produces: 123.00

sctemplarknight at hotmail dot com
12-Dec-2001 10:27


number_format($number,$precision,".","") should be used when setting the value of form elements because if you read the number into a double upon submission, it will only store digits before the comma.


<p>


ie. <input type="text" value="<?php echo(number_format(2.5343,2,".","")">

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